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nataly862011 [7]
3 years ago
8

Whats the slope form?

Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

y = -x + 6

Step-by-step explanation:

Slope intercept form is y=mx+b

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Simplify (3x)-1. A. 81x^4. B. 4x^6. C. 1/3x. D. 1/x^6
elena55 [62]
If you mean: (3x)^-1

When you have a power to a negative number (1 in this case), place the power on the numerator, with the base in the denominator.

(3x)^-1 = 1/3x

1/3x, or C) is your answer


hope this helps
3 0
3 years ago
Identify the graph of the compound inequality (-2 < 2x -6)
cupoosta [38]
Plug in 0 for z
 so it would change to -2<6 
6 0
3 years ago
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Ana uses Talk-A-Lot and Peter uses Talk-to-Me. Each company charges
mr Goodwill [35]

Answer:

They both talk for a different amount of time

7 0
3 years ago
How to do question 5 and 6. Can you explain the first one which is A for 5 and 6?<br><br>Thank you​
Illusion [34]

for 6

in a

given

slope(m)=1

point=(2,-4)=(x1,y1)

we know

equation of straight line

y-y1=m(x-x1)

y+4=1(x-2)

y+4=x-2

therefore x-y-6=0 is the required equation

substituting with ax+by+c=0 we get

a=1

b= -1

c= -6

4 0
3 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
Read 2 more answers
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