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r-ruslan [8.4K]
3 years ago
14

a university is comparing the grade point averages of biology majors with grade point averages of engineering majors. the univer

sity wants to test whether there is a significant difference in the hpa for students in the two majors what are the null and alternative hypotheses that should be used to test this claim
Mathematics
1 answer:
Ronch [10]3 years ago
7 0

Answer:

H0 : μEng = μBio

H1: μEng ≠ μBio

Step-by-step explanation:

μEng = Engineering average gpa

μBio = Biology average gpa

To test for difference between two sample means , in this case grade point average of biology majors and Engineering major.

Null hypothesis is the initial truth, which is that ; there is no difference in the mean grade point average of both biology and engineering majors

H0 : μEng = μBio

The Alternative hypothesis is the opposite of the null, which is stated has ; there is difference between the average GPA of both Engineering and Biology majors

H1: μEng ≠ μBio

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Doña Gertrudis recolecta en promedio 75 litros de leche de cabra por día y utiliza alrededor de 5 litros para hacer un kilogramo
Nimfa-mama [501]

Answer:

825 pesos a day on average

1 dozen weight = 2.4 kg

Step-by-step explanation:

In ENGLISH:

Doña Gertrudis collects on average 75 liters of goat milk per day and uses around 5 liters to make one kilogram of cheese. The cheeses he makes weigh 200 grams each and he sells them for 132 pesos a dozen. How much money do you get per day on average from the sale of your cheeses? How many kilograms does the dozen cheeses weigh?

<u>Solution:</u>

75 Liters / 5 Liters = 15

15 * 1 kg = 15 kg of cheese per day

15kg in grams is 15*1000 = 15,000 grams

Each cheese block is 200 grams, so number of blocks of cheese:

15,000/200 = 75 blocks of cheese

1 dozen (12) = 132 pesos, so 1 would be:

132/12 = 11 pesos PER BLOCK

SO, 75 blocks of cheese = 75 * 11 = <u>825 pesos (per day on average)</u>

<u></u>

Dozen cheese weight in kg,

200 grams * 12 = 2400 grams

In kg,

2400/1000 = <u>2.4 kg</u>

8 0
3 years ago
Find the mean, median and mode from the chart below ​
BlackZzzverrR [31]

Answer:

1. mean=1.5, median=1.7, mode is 1.8

2. mean=102,median=134, mode=no mode

3. mean=1885,median=2300, mode=2300

Step-by-step explanation:

6 0
3 years ago
Prove that : cos10° - sin10° / sin10° + cos10° = tan35°​
Digiron [165]

Step-by-step explanation:

(cos 10° − sin 10°) / (cos 10° + sin 10°)

Rewrite 10° as 45° − 35°.

(cos(45° − 35°) − sin(45° − 35°)) / (cos(45° − 35°) + sin(45° − 35°))

Use angle difference formulas.

(cos 45° cos 35° + sin 45° sin 35° − sin 45° cos 35° + cos 45° sin 35°) / (cos 45° cos 35° + sin 45° sin 35° + sin 45° cos 35° − cos 45° sin 35°)

sin 45° = cos 45°, so dividing:

(cos 35° + sin 35° − cos 35° + sin 35°) / (cos 35° + sin 35° + cos 35° − sin 35°)

Combining like terms:

(2 sin 35°) / (2 cos 35°)

Dividing:

tan 35°

3 0
3 years ago
Analyze Corey’s work to find his error. What is Corey’s mistake? He substituted 80 for x instead of y. He should have added 88.2
Anni [7]

x is the temperature and y is the number of swimmers. If there are 80 swimmers, then y = 80 instead of x = 80

This is how Corey should have solved

y = 1.505*x - 88.21

80 = 1.505*x - 88.21 <--- replace y with 80

1.505*x - 88.21 = 80

1.505*x = 80 + 88.21 <--- add 88.21 to both sides

1.505*x = 168.21

x = 168.21/1.505 <--- divide both sides by 1.505

x = 111.767

x = 111.8

If there are 80 swimmers at the pool, then the possible outside temperature is roughly 111.8 degrees F. This temperature seems awfully large, so it's possible that Corey's regression equation has limited scope; in other words, it isn't too useful if x is outside a given interval

<h2><em><u> </u></em><em><u>IF </u></em><em><u>YOU </u></em><em><u>DONOT</u></em><em><u> </u></em><em><u>WANT </u></em><em><u>TO </u></em><em><u>READ </u></em><em><u>SO </u></em><em><u>MUCH </u></em><em><u>THEN </u></em></h2>

<em><u>PLEASE</u></em><em><u> </u></em><em><u>SEE </u></em><em><u>THE </u></em><em><u>ATTACHMENT</u></em><em><u> </u></em>

4 0
3 years ago
Human civilization, at least since the time of ancient Egypt, is on the order of 5000 years old. The age of the Earth is on the
olchik [2.2K]
Write and solve an equation of ratios:

5 *10^9 years       100 m
------------------- = --------------
   5 * 10^3 yrs            x

Reducing the first fraction,
              
             100 m
10^6 = ----------
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Solving for x,  x = ------------- = 10^(-4) m, or [10^(-1)] * [10^(-3))]
                                10^6
this comes out to one tenth of 1 millimeter.
5 0
3 years ago
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