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3 years ago

40/64 eqivalent fractions

Mathematics

1 answer:

statuscvo [17]3 years ago

8 0

5/8 is the answer you are looking for

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36 first-graders and 14 other students attended a school assembly. What percentage of the students at the assembly were first-gr

dimaraw [331]

Answer: 18%

Step-by-step explanation: Add 36 + 14 = 50

Then 36*50/100=18

5 0

3 years ago

What is value of x if 20x-10*110=50

Tju [1.3M]

Answer:

57.5

Step-by-step explanation:

20x - (10 x 110) = 50

=> 20x - 1100 = 50

=> 20x = 1150

=> x = 1150/20

=> x = 115/2

=> x = 57.5

3 0

3 years ago

Find the distance between 4 2/3 and −5 1/3 on a number line. Write your answer in the simplest form.

jeka94

Answer:

3/25

Step-by-step explanation:

5 0

3 years ago

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago

If you answer this pls answer the other questions i asked for brainly

vlada-n [284]

Answer:

2 is the answer

Step-by-step2 explanation:

3 0

3 years ago

Read 2 more answers