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3 years ago

6

Given a regular octagon. write a plan for how you would determine the necessary measurements and calculations regular octagonal

square!

1 answer:

Alchen [17]3 years ago

3 0

Answer:

guvtuvpjb8hvigvpgnh b hrg ti b

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3x + 9 + 4x + x = inf many solutions

diamong [38]

No it just equals 8x+9

7 0

4 years ago

The length of a side of a square field is 48m.Find the cost of ploughing the field at the rate of rs 25/m and cost of fencing th

brilliants [131]

Answer: rs 4800, rs 3456

Step-by-step explanation:j

given data:

length of a sid = 48m

cost of ploughing the field = rs 25/m

cost of fencing the field = rs 18/m

solution:

we know a square has four equal sides. so total length of the field is

= m ( 48 + 48 +48 + 48 )

= 192m

cost of ploughing the field

= 192m * rs 25

= rs 4800

cos of fencing the field

= 192m * rs 18

= rs 3456

8 0

3 years ago

What are the solutions to the equation x² = 256?

tester [92]

The correct answer would be 128.

7 0

4 years ago

Read 2 more answers

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

Inseri the missing number.<br> 8 5 2<br> 4 2 0<br> 9 6 ?

UNO [17]

The answer is: 3

Explanation: there’s a number pattern going on, in the first example they subtract by 3 each time. In the second example they subtract by 2 each time. So for the last one you have to do 9-6 which is 3 and that’s the number pattern.

Hope I helped :)

8 0

3 years ago