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3 years ago

What is the original price if there is a 10% discount and the sale price is $76.50

Mathematics

1 answer:

Mrac [35]3 years ago

8 0

Answer: $84.15

Step-by-step explanation:

We need to find 10% of $76.50 to add it to get the original number.

Formula to get 10% of $76.50: (10*76.50)/100=$7.65

Now we add $7.65 to get the original price

$76.50+$7.65=$84.15

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A computer and printer cost total of $927 the cost of the computer is two times the cost of the planet find the cost of each ite

swat32

The cost of the printer is $309 and cost of the computer is $618.

Step-by-step explanation:

Let x denote the cost of computer

Let y denote the cost of printer

Total cost of printer and computer OR

x + y = $927

Cost of computer = 2 x cost of the planet

x = 2y

x+y = 927

2y+y = 927

3y = 927

y = 309

x = 2y

x = 2(309)

x = 618

Therefore, the cost of the printer is $309 and cost of the computer is $618.

Keyword: Cost, Algebra

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3 years ago

The expression 5n+2 can be used to find the total cost in dollars of bowling where n us is the number of games bowled and 2 repr

sukhopar [10]

Plug in the known variables.

5n + 2 n = number of games bowled

5(3) + 2 = 15 + 2 = 17

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3 years ago

Wha is the name of the line that you use to define a parabola?

Basile [38]

Answer is:

Directrix - D.

8 0

3 years ago

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John has 20 pieces of candy left for Halloween.He gave his brother 3 pieces his parents 4 pieces and his dog ate 1 piece.How man

andrew11 [14]

He gave away 8 so he would have 12/20 which is 60% left :)

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3 years ago

Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length

Bezzdna [24]

Answer:

Area of ΔDEF is $45\ cm^2$ .

Step-by-step explanation:

Given;

ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = $2\ cm$ and

Length of DE = $6\ cm$

Area of ΔABC = $5\ cm^2$

Solution,

Since, ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

$\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}$

Where triangle 1 and triangle 2 is ΔABC and ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

$\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2$

Thus the area of ΔDEF is $45\ cm^2$ .

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3 years ago

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