Answer:
1/2 ornament in an hour
Step-by-step explanation:
Given
Required
Determine the ornaments per hour
This question implies that we calculate the unit rate.
Substitute values for Time and number of ornaments
<em>This implies that Constance can decorate 1/2 ornaments in an hour</em>
C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
Cody ALONE = 8 hours
Kaitlyn ALONE = 6 hours
Let Joseph ALONE take j hours
Cody ALONE in 1 HOUR = 1/8 of the work Kaitlyn ALONE in 1 hour = 1/6 of the work Joseph ALONE in 1 HOUR = 1/j of the work
Since TOGETHER they take X hours, in 1 hour TOGETHER they complete 1 / X of the work
1/8 + 1/6 + 1/j = 1/X
1/j = 1/X - 1/8 - 1/6 = (24 - 3X - 4X ) /24X = (24 - 7X ) / 24X
j = 24X / ( 24- 7X )
After completing the work value of X will be known , calculate j from the above formula ANSWER
<span>1.) Circumscribed angle 2.) Minor arc 3.) Central Angle 4.) Inscribed Angle 5.)Major Arc</span>
Answer:
Yes, F is a continuous function of r
Step-by-step explanation:
We are given that
When r<R
Where M=Mass of the earth
R=Radius of earth
G=Gravitational constant
We have to find the function is continuous of r or not.
LHL
RHL
When a function is continuous at x=a
Then, LHL=RHL=f(a)
RHL==LHL=F(R)
Hence, the function is continuous of r.
