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2 answers:
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Answer:
0.1111
Step-by-step explanation:
Given that you roll two dice.
the average of the high and low roll is exactly 3,
Since die can show only 1 to 6 we can say average can be 3 in each of the following case.
(1,5) (2,4) (3,3) (4,2) (5,1)
There cannot be any other combination to get average of 3.
Thus favourable events = 4
Sample space will have
(1,1)...(1,6)
(2,1)....
(6,1)...(6,6) i.e. 36
So probability that the average of the high and low roll is exactly 3
=
We have events:
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:
so:
</span>
A - <span>customer orders a chicken sandwich
</span>B - <span>customer orders french fries
and probabilities:
so:
</span>