Question

the length of a room is 2 m longer than its breadth .if the area of its floor is 63 sq.m.calculate the length and the breadth of the room​

Answer 1

Answer:

Given :-

the length of a room is 2 m longer than its breadth .if the area of its floor is 63 sq.m.calculate the length and the breadth of the room

To Find :-

Length and breadth

Answer :-

Let the length and breadth be l + 2 and l

Now,

$\large \sf \: Area = l + 2 \times l$

$\large \sf \: 63 = l + 2 \times \: l$

$\large \sf \: 63 = 2l + {l}^{2}$

$\large \sf \: {l}^{2} + 2l - 63 = 0$

$\large \sf \: {l}^{2} (9l - 7l) - 63 = 0$

$\large \sf \: l(l + 9) - 7(l + 9)$

Either

$\large \sf \: l = - 9$

or,

$\large \sf \: l = 7$

Length can't be negative,

So,

L = 9

B = 7

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