Answer:
The time complexity of the code is O(log₇n).
Explanation:
The i is updated by 7*i.On each iteration i is multiplied by 7.So on finding the time complexity of the code given above it will come out to be log base 7.
When we divide the input by 2 the time complexity is log base 2.
So on dividing it by 7 we get the time complexity of log base 7.
Answer:
A) It simplifies the process by providing a single user interface for multiple software tools.
Explanation:
Answer:
if (x > 7 && Math.sqrt(x) < 3)
Explanation:
The previous condition checks if the square root of x is less than 3, but this would raise an error if x is a value equal to or less than 0.
So, the condition checks for the value of x before evaluating the square root after the AND operation to prevent an arithmetic exception.
Algorithms: rules to follow when problem-solving
Answer:
4 bits
Explanation:
With 4 bits you can count to 15, because 2⁴=16. The maximum number you can express is always one less, i.e., 16-1=15.
In general, with n bits you can count to 2ⁿ-1.
