Equation in vertex form, y= (-1/4) x² + 4
<u>Step-by-step explanation:</u>
we have the equation,
y = ax² + 4 ( we need to find "a")
Now we have,
2 = a(4)2 + 4
2 = a (8)+ 4
2-4 = 8a
-2= 8a
a= -1/4
Substituting the value of "a" in the equation, we have
y = (-1/4)(x- 0)² + 4 (or) y= (-1/4) x² + 4
The parabola is opens downward. Therefore the vertex is above the x-axis and then the parabola passes through a point below the x-axis.
Equation in vertex form= y= (-1/4) x² + 4
Answer:
the answer is 20.5 i hope this helps you
Step-by-step explanation:
Step-by-step explanation:
I think the equation should be
483 x 4 = h
1932 = h
Answer:
a = 10
Step-by-step explanation:
fill in the blank 10-6=4
check by adding 4 +6
have a nice evening :) :) :)
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
