Answer:
How do you solve what?
Step-by-step explanation:
The answer is 63,800 mi²
hoped this helps
JKM = M + L
15x - 48 = 40 + 5x + 12
10x - 48 = 52
10x = 100
x = 10
JKM = 15(10) - 48 = 102
180 = JKM + MKL
180 = 102 + MKL
MKL = 180 - 102 = 78
Answer:
The smallest of the said odd numbers is 27
Step-by-step explanation:
Since it is 3 odd numbers that sums up to 87, the first thing to do is to divide 87 by 3
That is 87/3 = 29, which is an odd number
The nearest odd numbers to 29 are 27 and 31, and the total of all these three odd numbers is 87
That is 27+29+31 = 87, which are consecutive odd numbers.
The smallest odd number here is therefore 27
Answer:
20
Step-by-step explanation:
an integer m is divisible by both 10 and 12
Lets write the prime factor for each number
the prime factor for 10 is 5,2
the prime factor for 12 is 3,2,2
Now take the product of the prime factors that are not in common and also in common
60 is divisible by 20
so answer is 20
