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anyanavicka [17]
3 years ago
13

There is a bag filled with 6 blue and 5 red marbles.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

Um

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How does finding the square root of a number compare to finding the cube root lf a number? Use the number 64 in your explainatio
xenn [34]

If you want to know the concept of square roots and cube roots ?

the square root of a number is that number which when multiplied by itself two times gives us that number

e.g.

√64 = x , so that (x)(x) = 64

and from our multiplication table we know that

(8)(8) = 64 , so that

√64 = 8

the cube root of a number is that number which when multiplied by itself three times gives us that number

e.g.

∛64 = x , so that (x)(x)(x) = 64 , and thus x = 4 because 4x4x4 = 64

so ∛64 = 4

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3 years ago
Are there any clusters or outliers in the scatter plot?
IrinaVladis [17]
The correct answer is D because there is one area that is a cluster (bundle of dots in one area) and one outlier (away from all the other points; irrelevant).
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Identify all the sets to which the number 0.41567. . . . belongs. Choose from rational, irrational, whole, and integer.
Shkiper50 [21]
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6 0
3 years ago
The function f(x)=log0.75x is decreasing. <br> True or false
Lerok [7]

Answer:

True

Step-by-step explanation:

Apex

6 0
3 years ago
Is there any video related to this or can you explain how to do it
uranmaximum [27]

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

4 0
3 years ago
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