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3 years ago

5 1/2 of what number is 55?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

8 0

I hope this helps you

BARSIC [14]3 years ago

8 0

5.5(x)=55
5.5(10)=55
55=55

X is 10 because when you multiply a decimal by 10, it moves the decimal point over one place to the right.

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Mrs. Davis went to a produce market to buy bananas and strawberries. She spent $8.00. If the bananas were $0.50 per pound, and t

9966 [12]

9514 1404 393

Answer:

4 pounds

Step-by-step explanation:

Let b represent the pounds of bananas Mrs. Davis bought. The weight of strawberries would be (7-b) and their cost would be 4×0.50 = 2.00 per pound. Her total purchase was ...

0.50b + 2.00(7 -b) = 8.00

-1.50b +14 = 8 . . . . simplify

6 = 1.50b . . . . . . add 1.50b -8

4 = b . . . . . . . . divide by 1.50

Mrs. Davis bought 4 pounds of bananas.

7 0

2 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

2 years ago

Is 18-3(2p+4)-3p equal to 3(2-3p)

Harrizon [31]

LHS=18-3(2p+4)
=18-6p-12
=6-6p
=3(2-2P) hence it is not equal to 3(2-3p)

7 0

3 years ago

Help plz I really need help could you show your work if you do it plz.

Vika [28.1K]

What do you need help with?

7 0

3 years ago

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Ratling [72]

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$ .

4 0

3 years ago