Answer:
Step-by-step explanation:
Answer=b=1
Answer:
1 Factor out the common term 22.
2(2x+y)=102(2x+y)=10
2 Divide both sides by 22.
2x+y=\frac{10}{2}2x+y=
2
10
3 Simplify \frac{10}{2}
2
10
to 55.
2x+y=52x+y=5
4 Subtract yy from both sides.
2x=5-y2x=5−y
5 Divide both sides by 22.
x=\frac{5-y}{2}x=
2
5−y
Step-by-step explanation:
1 Factor out the common term 22.
2(2x+y)=102(2x+y)=10
2 Divide both sides by 22.
2x+y=\frac{10}{2}2x+y=
2
10
3 Simplify \frac{10}{2}
2
10
to 55.
2x+y=52x+y=5
4 Subtract yy from both sides.
2x=5-y2x=5−y
5 Divide both sides by 22.
x=\frac{5-y}{2}x=
2
5−y
Step-by-step explanation:
Equation 1
Equation 2
Answer:
Books should be kept in second box.
Step-by-step explanation:
If the sum of all the weight of all books is between 4 and 6 pounds then it should be kept in first box
If the sum of all the weight of all books is between 5 and 7 pounds then it should be kept in second box
If the sum of all the weight of all books is between 8 and 9 pounds then it should be kept in first box .
Here sum of the weighs of all the books = 3.1lb+2.4lb +0.75lb
= 6.25 lb
Here we can see that 6.25 lb lies between 5 and 7 which is the weigh limit
for the second box
therefore we can keep the books in second box.
