A coin is tossed seven times and the sequence of heads and tails is observed. what is the number of different outcomes having ex
1 answer:
You could make a tree diagram
H T ← 1st toss
H T H T ← 2nd toss
H T H T H T H T ← 3rd toss
etc ,,, then count the combination of favorable outcomes
Using a calculator:
Total number of outcomes is
= 128
Probability of getting exactly 3 heads is found using the follow calculator feature: binompdf(7, 0.5, 3)
ANSWER: Typed into the calculator as follows binompdf(7,0.5,3)×128 = 35
H T ← 1st toss
H T H T ← 2nd toss
H T H T H T H T ← 3rd toss
etc ,,, then count the combination of favorable outcomes
Using a calculator:
Total number of outcomes is
Probability of getting exactly 3 heads is found using the follow calculator feature: binompdf(7, 0.5, 3)
ANSWER: Typed into the calculator as follows binompdf(7,0.5,3)×128 = 35
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Answer:
Step-by-step explanation:
He already has songs = 41
Since we are given that he purchase four songs every week .
So, in first week he purchase songs = 4
Initially he already has 41 songs
So, total songs after 1 week =
After 2 weeks he will have songs =
This forms an arithmetic sequence : 41,45,49......
Formula of nth term in A.P. :
a = first term = 41
d = common difference = 45-41=49-45=4
Since we are required to find the new songs after110 weeks
So, n =110
Substituting values :
Thus Option A is correct.
Answer:
Step-by-step explanation:
-4(-6x + 5) = 4
Divide both sides of the equation by -4
-6x + 5 = -1
Subtract 5 from both sides of the equation
-6x = 4
Divide both sides of the equation by -6
x = 4/-6
Simplify
Hope this helps :)