Yes, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 11, and get our simplified answer
Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Answer:
Markup amount: $54
New price with markup: $204
Step-by-step explanation:
36% markup to $150
We can find the amount of markup by finding 36% of 150.
36% of $150
Write 36% as a decimal and multiply it by the price
0.36(150) = $54
The amount of markup (36%) is equal to $54
When this is added to the original price, the new price is $150 + $54 = $204
Let me know if you have any questions!
Split the second term in 3a^2 - 8a + 4 into two terms
3a^2 - 2a - 6a + 4 = 0
Factor out common terms in the first two terms, then in the last two terms.
a(3a - 2) -2(3a - 2) = 0
Factor out the common term 3a - 2
(3a - 2)(a - 2) = 0
Solve for a;
a = 2/3,2
<u>Answer : B. (2/3,2)</u>
Answer:
es tal vez otra vez se repite la pregunta
