Vertex is now at (-1,5)
for
y=a(x-h)^2+k
vertex is (h,k)
so veertex is (-1,5)
y=a(x-(-1))^2+5
y=a(x+1)^2+5
a is a constant, we will asssume that it is 1 because all the choices have 1
y=1(x+1)^2+5
y=(x+1)^2+5
2nd option
Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:

To find the inverse of f(x) , equate f(x) to y
That's
y = f(x)
We have

Next interchange the terms that's x becomes y and y becomes x

<u>Next solve for y</u>
Move 3 to the other side of the equation
That's

<u>Divide both sides by 25</u>

We have the final answer as

Hope this helps you
19-20 = -1 u have to subtract left from tight <span />
Answer:
Given: y = x2 + 4x – 5
Find the following
y-intercept
x-intercepts or the zeros of the functions or roots
graph of the function, given vertex is at (-2, -9)
Solve the system of linear equations – x + 6y = 8 2x + 5y = 3
Write the names of curves, given their equations:
x2/16 + y2/9 = 1
3y = 2x + 5
(x - 5)2 + (y + 6)2 = 25
x2/16 – y2/25 = 1
y = 2x2 + 10x + 25
Write down the first five terms of the arithmetic progression with the first term 8 and common difference 7, then find the 17th
Write down the first five terms of the geometric progression with the first term 3 and common ratio 2, then find the 17th
Answer:
x5
Step-by-step explanation: