All categories

2 years ago

Write an expression for each

Mathematics

2 answers:

mart [117]2 years ago

5 0

15.Here

Let the length of square be l(length)
Perimeter of square = 4l
48cm= 4l
48/4= l
12=l
This,l=12 cm

faltersainse [42]2 years ago

4 0

15 cause my brothers in

You might be interested in

(02.01)Polygon LMNP slides 5 units right and 4 units down on the coordinate plane. If the original measure of angle M was 50 deg

yarga [219]

Answer:

50°

Step-by-step explanation:

Transformation is the movement of one point from its initial location to a final location. If an object is transformed, all its points are transformed. Types of transformation is reflection, dilation, rotation and translation.

If an object is translated, it maintains its shape and size as well as the length of its sides and angles, only the location changes.

If polygon LMNP with ∠M of 50° is translated 5 units right and 4 units down to a new point, M' has the same angle measure. Hence ∠M' = 50°

4 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Evaluate 5+\left(-3\right)-65+(−3)−65, plus, left parenthesis, minus, 3, right parenthesis, minus, 6.

Serga [27]

The question is not well-expressed, but it looks like you want to evaluate

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

Answer:

-140

Step-by-step explanation:

First of all, note the following

- Multiplying a negative number by another negative number gives a positive number.

- Multiplying a negative number by a positive number gives a negative number.

- Multiplying a positive number by a positive number gives a positive number.

- Brackets mean multiplication.

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

= 5 - 3 - 65 - 3 - 65 - 3 - 6

= -140

7 0

2 years ago

Please help me with number 22 and if you can part b to please

m_a_m_a [10]

It's not a good picture.it's not possible to read it

6 0

3 years ago

Find the area of the shape shown below.<br> HELP HELP HELP

KATRIN_1 [288]

8x3.5= ? That’s gonna be your answer.

3 0

2 years ago