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3 years ago

Please help me. Ion understand.

Mathematics

1 answer:

larisa86 [58]3 years ago

4 0

Answer:

Step-by-step explanation:

use SOH-CAH-TOA

sine= opposite/hypotenuse

cosine=adjacent/hypotenuse

tangent= opp./adj.

so that mean <JMK= 3/6 = 1/2

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Evaluate in the following expression when x = 4 and y = 5

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3.8
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23.5

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3 years ago

Algebra 2 will give points and brainly

aivan3 [116]

Answer:

Step-by-step explanation:

In the 3rd question, we are given the equation x ^ 3 + x ^ 2 + 2x + 24. One of the factors is x + 3. Now, we can use long division to find that the equation we have left is x^2 - 2x - 8. We can just factor this to get (x - 4) (x + 2). In the 3rd question, possible factors for the coefficient are 1, 2, -1, -2. Possible factors for the constant are 1, 7, -1, -7. Now, we can try out all of them. The possible factors are 1, 7, -1, -7, 2, 14, -2, -14.

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3 years ago

In this activity, you will use equations to represent this proportional relationship: Olivia is making bead bracelets for her fr

Valentin [98]

Answer:

Step-by-step explanation:

A) The constant of proportionality in terms of minutes per bracelet is

15/3 = 5 minutes per bracelet

B) The constant of proportionality represents man hour rate

C) let k = constant of proportionality, t = time in minutes and b = number of bracelets produced. Therefore,

t = kb

D) the constant of proportionality in terms of number of bracelets per minute is

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3 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

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(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

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So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
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which is approximately 1.546.

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$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

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3 years ago

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oksian1 [2.3K]

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