If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l
now
solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum
notice the
so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0
so.. check the critical points on the other
The ilne paralell to x=something is x=something else (both are constants)
slope=rise/run
x=-3
it rises infiniley and runs 0 (goes left to right 0)
slope=infinity/0=undefined
the slope is undefined
paralell lines have same slope
so the slope of a paralell line is also undefined
Slope is 4/3, y intercept is 2, equation is y=4/3x +2
Answer:
x = 10 or x = 2
Step-by-step explanation:
Solve for x:
x^2 - 12 x + 20 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 20 from both sides:
x^2 - 12 x = -20
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 36 to both sides:
x^2 - 12 x + 36 = 16
Hint: | Factor the left hand side.
Write the left hand side as a square:
(x - 6)^2 = 16
Hint: | Eliminate the exponent on the left hand side.
Take the square root of both sides:
x - 6 = 4 or x - 6 = -4
Hint: | Look at the first equation: Solve for x.
Add 6 to both sides:
x = 10 or x - 6 = -4
Hint: | Look at the second equation: Solve for x.
Add 6 to both sides:
Answer: x = 10 or x = 2
Answer:
Sedimentary rocks usually form in visible layers
Step-by-step explanation:
A is wrong because not all igneous rock is formed by pressure
B is wrong because sedimentary rock is usually a surface rock
C is wrong because the rock cycle is sporadic and doesn't always end in igneous rock
D is correct because sedimentary rock is formed from years and years of sediment layering on top of each other
