1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergeinik [125]
3 years ago
12

At a health club, 60% of the members are men and 40% of the members are women. The average age of the men is 32 years. The avera

ge age of the women is 28 years.
What is the average age of all the members of the health club?
Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

30.4 percent. Hope this helps!

Step-by-step explanation:

You might be interested in
Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

7 0
3 years ago
The area of an equilateral triangle with a 6 inch apothem
skad [1K]
Answer is 187.06 and the work is in the attached picture.

6 0
3 years ago
What is the unit rate of 115miles in 2hours
maksim [4K]
You would divide miles to hours amd get 57.5
5 0
3 years ago
Read 2 more answers
“which of the <br> equations below could be the equation of this parabola?”
luda_lava [24]
The answer is C because it is on the x axis and it is positive
3 0
2 years ago
Read 2 more answers
What is the mean absolute deviation of the following set of data?<br> 4<br> 6<br> 6<br> 2.
MariettaO [177]

Answer:

To calculate the mean we need x and f both

7 0
3 years ago
Other questions:
  • A study of parents of kindergarteners included 349 parents who were chosen at
    8·1 answer
  • after 1 second the ball is 76 feet in the air: after 2 seconds it is 144 feet in the air. Find the height of the function. h(x)=
    7·1 answer
  • How to solve surface area triangular prisms
    11·1 answer
  • Three rational numbers between 16 and 15
    7·2 answers
  • The art club has 12 members who are sixth graders 18 members who are seventh graders and 10 members who are eighth-graders. What
    12·1 answer
  • 11. What is the slope-intercept equation of the line with slope 7 that passes through the point (1, 2)?
    11·1 answer
  • Maddie buys stock that is worth $22 per share. On the first day, the value of the stock goes up 20%. On the second day, the valu
    15·1 answer
  • PLEASE HELP ASAP AND NO VIRS!
    13·1 answer
  • Please help with this equation:<br><br> 4.5(8-x)+36=102-2.5(3x+24)
    9·1 answer
  • Plz help ASAP!!!!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!