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3 years ago

Are these proportional? 3/2 and 18/8

Mathematics

1 answer:

OLEGan [10]3 years ago

3 0

Answer:

For two fractions to be proportional, they must be equivalent. 32=1.5 and 188=2.25 , so these fractions are not proportional.

Step-by-step explanation:

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Degger [83]

Answer:

Step-by-step explanation:

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2 years ago

Need help right now asap??!?!?!??!?!??!

abruzzese [7]

A) The person that has a greater probability of selecting a quadrilateral is Robert.

B) The person that has a greater probability of selecting a polygon is; Robert.

C) The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

<h3>How to Identify Polygons?</h3>

Sandy has; Square, Rhombus, Equilateral Triangle, Regular Hexagon

Robert has Scalene Triangle, Kite, Right Isosceles Triangle, Isosceles Trapezoid, Quadrilateral.

A) Sandy's probability of selecting a quadrilateral = 2/4 = 0.5

Robert's probability of selecting a quadrilateral = 3/5 = 0.6

The person that has a greater probability of selecting a quadrilateral is Robert

B) The person that has a greater probability of selecting a polygon is; Robert because he has more.

C) Probability of Sandy selecting a polygon with at least 2 sides parallel is; 3/4 = 0.75

The Probability of Robert selecting a polygon with at least 2 sides parallel is; 2/5 = 0.4

The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

Read more about Polygons at; brainly.com/question/5715879

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6 0

2 years ago

PLEASEEEEEE SOMEONE HELP I WILL GIVE ALOT OF POINTS AND WHATVER ELSE PLEASEE

Triss [41]

Part A : formula for circumference = pi*D or 2piR
for circle A.... 8*pi=25.12
therefore pi=3.14
for circle B.... 3*pi=9.42
therefore pi=9.42/3
pi=3.14

part B : formula for Area =
$pi \times {r}^{2}$
for circle A.... 50.24=pi*(8/2)sqr...(because diameter/2= radius)
pi=50.24/16
pi=3.14

for circle B... 7.065=pi*(3/2)sqr...
pi=7.065/2.25
pi=3.14

what do you observe?
the values for pi are all equal... therefore pi is constant.

4 0

4 years ago

PLZ PLZ PLZ PLZ PLZ PLZ HELP I NEED HELP PLZZZZZZZZZ NO ONE HAS HELPED ME FOR AN HOUR 25 POINTS

Margarita [4]

Answer:

C, D, A

Step-by-step explanation:

Distributive property

Combining like terms

Communitive property

8 0

3 years ago

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago