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3 years ago

I need helppp ! please help me this is due soon

Mathematics

2 answers:

SashulF [63]3 years ago

6 0

Answer:y=(-1x)-4

Step-by-step explanation:

steposvetlana [31]3 years ago

3 0

Answer:choice number 3

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Jonathan collects postcards and stamps. The number of postcards in his collection is 12 more than 3/4 the number of stamps. He h

zimovet [89]

For this case we define the following variable:

<em>x: number of stamps </em>

We now write the equation that models the problem:

$\frac {3} {4} x + 12 = 39$

From here, we clear the value of x.

We have then:

$\frac {3} {4} x = 39-12\\\frac {3} {4} x = 27\\x = (\frac {4} {3}) (27)\\x = (4) (9)\\x = 36$

Answer:

The number of stamps he has is:

$x = 36$

7 0

3 years ago

Read 2 more answers

You would like to have $8000 in an account after four years time if the account earns 4% compound interest yearly how much would

Mariana [72]

Answer:

http://www.1728.org/compint2.htm

Principal = Total ÷ (1 + Rate) ^ years

Principal = $8,000 / (1.04) ^ 4

Principal = $8,000 / 1.16985856

Principal = 6,838.43

Step-by-step explanation:

5 0

3 years ago

Lines m and n are parallel. Which of the other 5 named angles have a measure of 110°?

Cloud [144]

Answer:

2 and angle that is left of 5

Step-by-step explanation:

Angle 2 is vertical from 110, and vertical angles are congruent. From this, we can figure out that 2 and 3 (they're supplementary) are 70. Angles 5 and 3 are Alternate Interior Angles, and therefore must be congruent. The one to the left of 5 is supplementary to it, and therefore must be 110. Your answers are angle 2 and the angle that is left of 5.

4 0

4 years ago

. You are interested in the amount of time teenagers spend weekly working at part-time jobs. A random sample of 15 teenagers was

agasfer [191]

Answer:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

Step-by-step explanation:

Information given

$\bar X=147.3$ represent the sample mean for the amount of time spent at part time jobs

$s=50$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =120$ represent the value to check

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to analyze if the true mean for the amount of time spent at part time jobs is higher than 120, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

Since we don't know the population deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

4 0

3 years ago

Round 13.467 to the nearest<br> hundredth.

eimsori [14]

Answer:

69.420π% c69 17o42

Step-by-step explanation:

hitler

7 0

3 years ago