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2 years ago

-3x - 4y = 2

Mathematics

1 answer:

Sati [7]2 years ago

3 0

y = -5/4, x = 9/4

working:

isolate y for -3 - 4y = 2 : y = -5/4

Substitute y = - 5/4

[x - 5/4 = 1]

isolate x for x - 5/4 = 1 : x = 9/4

FINALLY ANSWER:

y = -5/4, x = 9/4

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Which number is IRRATIONAL? A) 47 B) 0.09 C) 15 D) 8 45

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3 years ago

Find the value of x, y, and z in the figure below: ہ 2y IN 2x 90° t

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2 years ago

five people, each working 8 hours a day, can assemble 400 toys in a five day work week. what is the average number of toys assem

vladimir1956 [14]

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3 years ago

Read 2 more answers

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago