360/0.96 or 510/1.44
360/0.96
0.96/360
.........3.76
_________
96/36000
......288
___________
.........720
.........672
_________
...........580
............576
_________
.................4
___________
510/1.44
............354
____________
144/ 51000
.........432
________
780
720
---------------
600
576
------------------
24
360g at $0.96 is best deal
Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 






The sample size needed is 2401.
is there a picture? if there is I cant see it
Answer:
Hey :)
Step-by-step explanation:
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