The sum of opposite angles are equal, so two of the angles are 45°. The sum of all angles about the intersection of two lines is 360°. So the remaining two angles are found by:
α=(360-2*45)/2
α=135° thus all four angles are:
45°,135°,45°,135°
Answer:
the answer to this equation is 55
X= 130°
Step-by-step explanation:
From E, draw EF || AB || CD.
Now, EF || CD and CE is the transversal.
So; <DCE + <CEF = 180° [co. int. <s]
x° + <CEF = 180°
<CEF = (180° – x°).
Again, EF || AB and AE is the transversal.
So; <BAE + <AEF = 180° 01 [co. int. <s ]
105° + <AEC+ <CEF = 180°
105° +25° + (180° – x°) = 180°
x° = 130°
I hope I helped you^_^
Answer:
y³ - 3y² + 1/y+3
Step-by-step explanation:
y² - 9 = (y - 3) ( y + 3)
y-3/(y-3)(y+3) = 1/y+3
