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Alekssandra [29.7K]
3 years ago
6

What evidence do we have that the planets travel around the sun?

Physics
1 answer:
Softa [21]3 years ago
5 0

Answer : The four seasons

Explanation:

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How is a well different from a spring?
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Answer:

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How far something moves in a specific amount of time
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Distance is how far something moves in a specific amount of time. 
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The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0
AysviL [449]

The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t  represented by function :

p(t)=t^{2} +2t-4

Now,

When  function p(t) = 11 , t will be

p(t)=t^{2} +2t-4

11 = t²+2t-4

0 = t² + 2t - 15

or

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0  

t = 3 , -5  

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = \frac{position}{time}

therefore to get the value of velocity from  function p(t)

we have to differentiate the function with respect to time

\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)

v(t) = 2t + 2  

where v(t) = velocity at that time

as t = 3 for  p(t)=11  

so ,

v(t) = 2t + 2  

v(t) = 2*3 + 2  

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

To know  more about function here:

brainly.com/question/12431044

#SPJ4

4 0
2 years ago
Within any ecosystem, there is a fixed amount of energy available for organisms to use. Since organisms usually produce more off
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I'm going to say carrying capacity since carrying capacity is the maximum amount of organisms that can live in an ecosystem. So the reason for there being a maximum of organisms is because, like the question says, organisms usually produce more offspring than the ecosystem can support.
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A circular loop of wire having a radius of 5.58 cm carries a current of 0.230 A. A vector of unit length and parallel to the dip
Sidana [21]

Answer:

see explanation

Explanation:

Given quantities:

radius = r = 0.0558 [m]

current = I = 0.23 [A]

\vec{B} =

Now we solve this by obtaining the torque acting on the dipole

\tau = M \times B

We obtain the magnetic moment vector M, first, |M| is defined as M = IA, where A is the cross-section area of the loop which is A = \pi r^2=\pi (0.0558)^2= 0.00978 [m^2] then

|M| = 0.23*0.00978 = 0.00225 [A/m^2]

now the magnetic moment vector is equal to the magnetic dipole moment vector multiplied the magnitude we just obtained  \vec{M} = M \hat M

= 0.00225 *

Now:

a ) \tau = M \times B

b) U = -M \cdot B

a) the determinant gives us:

b) the dot product gives = -1*-7.2*10^{-6} = 7.2*10^{-6}[J]

6 0
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