Use the Ideal Gas Law to the air in the tire :
( P ) ( V ) = ( n ) ( R ) ( T )
n = ( P ) ( V ) / ( R ) ( T )
P = P gauge + P baro = 31.2 psig + 14.8 psia = 46 psia
P = ( 46 psia ) ( 1 atm / 14.696 psia ) = 3.13 atm
n = ( P ) ( V ) / ( R ) ( T )
n = ( 3.13 atm ) ( 4.6 L ) / ( 0.08206 atm - L / mol - K ) ( 26.0 + 273.2 K )
n = 0.5864 moles
m = ( n ) ( M )
m = ( 0.5864 mol ) ( 28.96 g/ mol ) = 16.98 g
A contact force is a type of force which act on an object by coming in contact with the object. Examples of contact force that acts through a force field are: applied force, frictional force, air resistance force, tension, spring force, etc.
Examples of forces that act through a force field are gravitational force, electromagnetic force, the weak interaction and the strong interaction.
Answer:
b
i remember this question from when i had a test to take.
Explanation:
It is given that,
Initial speed of a golfer, u = 29 m/s
If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.
(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.

Here,
a = -g
s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).
So,

So, it will take 4.184 seconds in the air.
(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :

Hence, this is the required solution.