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xenn [34]
3 years ago
10

Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two object

s is reduced in
half, what will be the changed force of attraction between them?
Physics
2 answers:
givi [52]3 years ago
5 0

Answer:

Four times higher

Explanation:

F- G (m1 x m2)/ r^2

if r 1  = 2 and r 2 = 1       therefore  F = G (m1 x m2)/  1^2 is 4 times higher than

                                    2^2 since G and m1  and  m2 remained the same

Pepsi [2]3 years ago
5 0

answer is D. 20 newtons for plato, got 100 on the test :)

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How many moles of gas must be forced into a 4.6 l tire to give it a gauge pressure of 31.2 psi at 26 âc? the gauge pressure is r
Bess [88]
Use the Ideal Gas Law to the air in the tire : 

( P ) ( V ) = ( n ) ( R ) ( T ) 
n = ( P ) ( V ) / ( R ) ( T ) 
P = P gauge + P baro = 31.2 psig + 14.8 psia = 46 psia 
P = ( 46 psia ) ( 1 atm / 14.696 psia ) = 3.13 atm 
n = ( P ) ( V ) / ( R ) ( T ) 
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7 0
3 years ago
Name one contact force and one force that acts through a force field
nirvana33 [79]
A contact force is a type of force which act on an object by coming in contact with the object. Examples of contact force that acts through a force field are: applied force, frictional force, air resistance force, tension, spring force, etc.
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5 0
4 years ago
Q: Why are distances in space often measured in light years?
marin [14]

Answer:

the answer is b

Explanation:

Hope it helps :)

6 0
4 years ago
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Economic growth as measured by gross domestic product does not really tell us much about citizens' general well-being. Consider
kotegsom [21]

Answer:

b

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4 0
3 years ago
A golfer imparts a speed of 29.0 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te
Roman55 [17]

Explanation:

It is given that,

Initial speed of a golfer, u = 29 m/s

If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.

(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.

s=ut+\dfrac{1}{2}at^2

Here,

a = -g

s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).

So,

0=29\sin(45)t-\dfrac{1}{2}\times 9.8t^2\ (\text{Initial vertical component of velocity is taken})\\\\-4.9t^2+29\times \dfrac{1}{\sqrt2}t=0\\\\-4.9t^2+20.5t=0\\\\t=0,4.184\ s

So, it will take 4.184 seconds in the air.

(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :

x=vt\cos\theta\\\\x=29\times 4.184\times \cos(45)\\\\x=85.79\ m

Hence, this is the required solution.

8 0
4 years ago
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