Answer:
11.34 m/s
Explanation:
Force F = 25 N
Lenght of application l = 16.5 cm = 0.165 m
Time of application t = 1 sec
Radius of wheel r = 33.0 cm = 0.33 m
Moment of inertia I = 1200 kg·cm^2 = 0.12 kg-m^2
Let us assume he rides a fixed gear bicycle so that one revolution of the pedal is equal to one revolution of the tire
Solution:
Torque T on pedal = F x l = 25 x 0.165 = 4.125 N-m
Rotational impulse = T x t = 4.125 x 1 = 4.125 N-m-s
Initial momentum of wheel = 0 (since it start from rest)
Final momentum of wheel = I x w
Where w = angular speed
I x w = 0.12w
Change of momentum = 0.12w - 0 = 0.12w
Rotational impulse = momentum change
4.125 = 0.12w
w = 4.125/0.12 = 34.375 rad/s
Tangential velocity of wheel = angular speed x radius of wheel
V = w x r = 34.375 x 0.33 = 11.34 m/s
Answer:
The answer is 3x² + 10x
Explanation:
d/dx (x³ + 5x² - 2)
= d/dx (x³) + 5 d/dx (x²) - d/dx (2)
= 3x² + 5(2x) - 0
= 3x² + 10x
Thus, The answer is 3x² + 10x
<u>-TheUnknownScientist</u>
Answer:
T= 19.74 N
Explanation:
The tension in the string will be equal to centripetal force on the ball. (Newton's 3rd law, equal acting and reacting forces acts on a body)
T = Fc
Fc = m w ²r
here:
m = 0.25 kg, r = 0.5 m
w = 2 rps = 2 * 2π rad/s ( ∴ 1 revolution = 2π radians )
w = 4π rad/s
Fc = m w ²r = 0.25 * ( 4π )² * 0.5 N
Fc = T = 19.74 N
T= 19.74 N
You cannot average the two speeds in conditions of equal distance. You need equal time..
Look at it this way: 15 m/s for 10 km would take 666.67 seconds.
25 m/s for another 10 km would take 400 seconds. Total time: 1066.67 seconds. Total distance 20 km. This average speed 20000 m/1066.67 seconds = 18.75 m/s.
If you had gone 15 m/s for the same *time* as going at 25 m/s, then you could have averaged the speeds directly.
To get a real feel for this, imagine going at 1 m/s for 10 km, and then going at the speed of flight for the other 10 km. The first part would take 10000 seconds (nearly 3 hours) and the second almost zero time. Would your average speed be half the speed of light?
Explanation:
m = kg. v=m/s. g=m/s^2. h= m
>>1/2mv^2=mgh
>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m
>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .
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