<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Answer:
where is the figure to denote angles??
25/45=(5∗5)/(5∗9)=5/9
5/9 is the answer.
Answer:
Step-by-step explanation:
Given function is,
f(x) = 
If the given function is vertically stretched by a scale factor of 
Or 1.5,
Transformed function will be,
h(x) = ![\frac{3}{2}[f(x)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bf%28x%29%5D)
h(x) = 
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) = 
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of then shifted 1 unit upward.
