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dlinn [17]
2 years ago
9

Help me on this please it’s due please help me

Mathematics
2 answers:
Aleks04 [339]2 years ago
8 0

Answer:

<

Step-by-step explanation:

<

mars1129 [50]2 years ago
7 0
The answer is < (more than)
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4 0
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Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

-x+10y=5       ...(iii)

On adding (i) and (iii), we get

7y=14

Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

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2 years ago
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a_sh-v [17]

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Step-by-step explanation:

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