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Lisa [10]
2 years ago
12

He is pulling 400 feet over level ground by exerting a constant 25-pound force on the bar that makes an angle of 30° with the gr

ound.
How much work is Thomas doing to pull the wagon?

10,000 foot-pounds
8,660 foot-pounds
7,070 foot-pounds
5,000 foot-pounds
Mathematics
2 answers:
Deffense [45]2 years ago
5 0

Answer:

b

Step-by-step explanation:

pochemuha2 years ago
4 0

Answer:

It’s b

Step-by-step explanation:

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Both answers are letter A. 
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Order these numbers from least to greatest. 3.4051, 5.229, 3.4, 3.45<br><br>​
Allushta [10]

Answer:

3.4, 3.4051, 3.45, 5.229

Step-by-step explanation:

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A book store sells a textbook for $150. If the textbook is on sale with 12% off, and there is a sales tax of 8.25% added to the
Yuri [45]

The textbook is $150 originally, so to find the price of the textbook on sale, multiply the original price by 12% (0.12). Then subtract 12% of 150 from 150.

  • 150 * 0.12 = 18

Subtract 18 from 150.

  • 150 - 18 = 132

Multiply the price of the textbook on sale by the sales tax of 8.25% (0.0825). Then add the tax price onto the sale price of the textbook.

  • 132 * 0.0825 = 10.89

Add 10.89 to 132.

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The final price of the textbook is $142.89.

4 0
3 years ago
If ƒ(x) = 5x − 2 and g(x) = 1 − 2x, find (ƒg)(x).
drek231 [11]

Answer:

A

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4 0
2 years ago
1.How many combinations are possible from the letters HOLIDAY if the letters are taken?
Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

Exercise 1, item a:

One letter from a set of 7, hence:

C_{7,1} = \frac{7!}{1!6!} = 7

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

C_{7,2} = \frac{7!}{2!5!} = 21

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

C_{7,7} = \frac{7!}{0!7!} = 1

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0
1 year ago
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