Question

Why can parents who are heterozygous for type A and type B blood have children with any of the four human blood types? Use a Punnett square to support your answer.

Answer 1

Answer:

B 0

A AB A0

0 B0 00

Explanation:

Hello!

A parent of phenotype A and heterozygous genotype (A0) can have two possible gametes A and 0.

A parent of phenotype B and heterozygous genotype (B0) can have two possible gametes B and 0.

When crossing the two parents we can see that the four blood types are possible in equal probability.

Genotype A0: phenotype A

Genotype B0: phenotype B

AB genotype: AB phenotype

Genotype 00: Phenotype 00.

Successes with your homework!

Answer 2

The parent's genotypes are $I^{a}$ and $I^{b}$ respectively. When crossed together, all possible genotypes can be expressed. 1/4 AB blood, 1/4 A blood (heterozygous), 1/4 B blood (heterozygous) and 1/4 O blood. A Punnett square has been uploaded to support this.