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sleet_krkn [62]
3 years ago
14

Make x the subject of the formula a − bx = c​

Mathematics
2 answers:
Eddi Din [679]3 years ago
3 0

Answer:

x = c - a / -b

Step-by-step explanation:

a - bx = c

-a               -a

-bx = c - a

divide -b    

x = c - a / -b

gogolik [260]3 years ago
3 0

Answer:

\frac{-c+a}{b}

Step-by-step explanation:

a - bx = c

use substition method:

-bx = c - a

-1(-bx = c - a)

bx = -c + a

then divide both sides by b:

bx/b = -c+a/b

x = \frac{-c+a}{b}

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3 years ago
Analyze the graph h(x).
Dominik [7]

Answer:

D h(x) = f(x)×g(x)

Step-by-step explanation:

h(x) has a wave with 2 changes in direction.

so, this needs to be an expression of the third degree (there must be a term with x³ as the highest power of x).

and that is only possible when multiplying both basic functions. all the other options would keep it at second degree (x²) or render it even to a first degree (linear).

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6 0
3 years ago
A map is drawn to scale such that 1 inch equals 100 miles. To mark a distance of 500 miles, the length on the map must be_____ i
Degger [83]

Answer:

5 inches

Step-by-step explanation:

its simple

1in-100m

500m= 100m x 5

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7 0
3 years ago
Read 2 more answers
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
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