3/4 + 1/2
multiply 1/2 denominator and numerator by 2 to match 3/4
= 3/4 + 2/4 = 5/4 (copy same denominator add numerator)
2/6 + 1/3
divide 2/6 denominator and numerator by 2 to match 1/3
= 1/3 + 1/3 = 2/3 (copy same denominator add numerator)
5/9 + 2/3
multiply 2/3 denominator and numerator by 3 to match 5/9
= 5/9 + 6/9 = 11/9 (copy same denominator add numerator)
6/9 -1/5
cross multiply 6x5 - 1x9 for numerator
for denominator multiply 9x5
=30/45 - 9/45= 21/45
divide num and den by 3
=7/15
5/8-1/3
cross multiply 5x3-1x8 for numerator
multiply 8x3 for denominator
= 15/24 -8/24 =7/24
Answer:
I'm not sure what the answer is but, I'm thinking the answer w
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².
To find the perimeter of each, we add the area of all sides. For the first figure, the missing sides are 1 cm and 6 cm. To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.
For the second figure, the missing sides are 4 cm and 3 cm. To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.
For the third figure, the missing sides are 3 cm, 3 cm and 8 cm. To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.
For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm. To find the area, we have two squares whose dimensions are 10x10.
For the fifth figure, the missing sides are 3 cm and 9 cm. To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
The answer would be x + y = 37 y = x + 5 x + (x + 5) = 37 2x = 32 x = 16 y = 21Hope I helped!
A=-3 and i think any value of 'a' makes those equation infinite solution because expression has same variable both side.
