Step-by-step explanation:
first you have to see the triangle BCD
then hypotheses and perpendicular are given so you have to find base
after finding base. In rectangle ABCD DC is length and BC is breadth so now you can find area by using the formula A = l×b
Answer:
No, it is not a square
Step-by-step explanation:
If one wall is 19", that would mean the wall perpendicular to this wall is also 19" (in fact all of the walls would be 19"!) If this was a square, then the diagonal we draw at 20.62" would serve as the hypotenuse of a right triangle. One wall would serve as a leg, and another wall as another leg. If this is a square, then the Pythagorean's Theorem would be satisfied when we plug in the 2 wall measures for a and b, and the diagonal for c:

We need to see if this is a true statement. If the left side equals the right side, then the 2 legs of the right triangle are the same length, and the room, then is a square.
361 + 361 = 425.1844
Is this true? Does 722 = 425.1844? Definitely not. That means that the room is not a square.
Find the domain of
y = log(x + 3)
Logarithms can only be taken for positive numbers. So you must have
x + 3 > 0
x > – 3 ✔
So the domain of the function is
D = {x ∈ R: x > – 3}
or using the interval notation
D = (– 3, +∞)
I hope this helps. =)
So each time, 24/12 or $2 was deducted per trip
he has 30-24=$6 left
$6/$2=3, he has 3 trips left
I wonder what your question is