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sweet [91]
3 years ago
11

7 4 8 1 Write down the largest even number you can using all four cards

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

8

7

4

1

Step-by-step explanation:

8 is the answer

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What is another way to write the expression ​ t⋅(14−5) ​?
grigory [225]

t⋅(14−5)

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14t -5t

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8 0
3 years ago
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The minibus runs at 16 miles to a gallon of diesel. Diesel costs £1.43 per litre. There are 4.55 litres to a gallon.
melomori [17]

Answer: it will cost £78.0672 to travel the 192 miles to Brighton.

Step-by-step explanation:

The minibus runs at 16 miles to a gallon of diesel. If there are 4.55 litres to a gallon and diesel costs £1.43 per litre, it means that the cost of a gallon of diesel would be

4.55 × 1.43 = £6.5056

This means that the cost of running 16 miles is £6.5056

Therefore, the amount that it will cost to travel the 192 miles to Brighton would be

(192 × 6.5056)/16 = £78.0672

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3 years ago
What is the solution 5x-15=-25
IRISSAK [1]

Answer:

x= -2

Step-by-step explanation:

MARK AS BRAINLIEST!!

4 0
3 years ago
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Square of a standard normal: Warmup 1.0 point possible (graded, results hidden) What is the mean ????[????2] and variance ??????
LenaWriter [7]

Answer:

E[X^2]= \frac{2!}{2^1 1!}= 1

Var(X^2)= 3-(1)^2 =2

Step-by-step explanation:

For this case we can use the moment generating function for the normal model given by:

\phi(t) = E[e^{tX}]

And this function is very useful when the distribution analyzed have exponentials and we can write the generating moment function can be write like this:

\phi(t) = C \int_{R} e^{tx} e^{-\frac{x^2}{2}} dx = C \int_R e^{-\frac{x^2}{2} +tx} dx = e^{\frac{t^2}{2}} C \int_R e^{-\frac{(x-t)^2}{2}}dx

And we have that the moment generating function can be write like this:

\phi(t) = e^{\frac{t^2}{2}

And we can write this as an infinite series like this:

\phi(t)= 1 +(\frac{t^2}{2})+\frac{1}{2} (\frac{t^2}{2})^2 +....+\frac{1}{k!}(\frac{t^2}{2})^k+ ...

And since this series converges absolutely for all the possible values of tX as converges the series e^2, we can use this to write this expression:

E[e^{tX}]= E[1+ tX +\frac{1}{2} (tX)^2 +....+\frac{1}{n!}(tX)^n +....]

E[e^{tX}]= 1+ E[X]t +\frac{1}{2}E[X^2]t^2 +....+\frac{1}{n1}E[X^n] t^n+...

and we can use the property that the convergent power series can be equal only if they are equal term by term and then we have:

\frac{1}{(2k)!} E[X^{2k}] t^{2k}=\frac{1}{k!} (\frac{t^2}{2})^k =\frac{1}{2^k k!} t^{2k}

And then we have this:

E[X^{2k}]=\frac{(2k)!}{2^k k!}, k=0,1,2,...

And then we can find the E[X^2]

E[X^2]= \frac{2!}{2^1 1!}= 1

And we can find the variance like this :

Var(X^2) = E[X^4]-[E(X^2)]^2

And first we find:

E[X^4]= \frac{4!}{2^2 2!}= 3

And then the variance is given by:

Var(X^2)= 3-(1)^2 =2

7 0
3 years ago
PLEASE HELP! NO ONE HAS BEEN HELPING WITH MY QUESTIONS SO IT WOULD MEAN A LOT IF YOU DID!
kvv77 [185]

Answer:

80 m²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (a + b)

where h is the perpendicular height between bases and a, b are the bases

Here h = 8, a = 14 and b = 6, thus

A = \frac{1}{2} × 8 × (14 + 6) = 4 × 20 = 80 m²

3 0
3 years ago
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