PLEASE HELP !! ILL GIVE 40 POINTS ; PLUS BRAINLIEST !! DONT SKIP ANSWER.

Lynna [10]

Answer: The rate of change in the y coordinate is 75. 78 - 3= 75.

5 0

2 years ago

Question 7 A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

QveST [7]

Answer:

1) $S=\{1,2,3,4,5,6\}$

2) $O=\{1,3,5\}$

Step-by-step explanation:

Given : A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

To find : Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling an odd number. If there is more than one element in the set, separate them with commas ?

Solution :

A number cube with faces labeled from 1 to 6 will be rolled once.

The sample space describing all possible outcomes is given by

$S=\{1,2,3,4,5,6\}$

All of the outcomes for the event of rolling an odd number is given by

$O=\{1,3,5\}$

6 0

3 years ago

The sum of a number times 6 and 5 equals 4 translate the sentence into an equation

yan [13]

If x is the number we get:-

6x + 5 = 4

3 0

3 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

METHOD - I

Sin² C + Cos² C = 1

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$

Tan C = $\frac{3}{4}$ 

METHOD - II

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

∵ ΔABC is Right triangle.

∴ By Pythagorean Theorem-

AB² + AC² = BC²

AC² = BC² - AB²

AC² = 5² - 3²

AC² = 25 - 9

AC² = 16

AC ( Base) = 4

Since,

Tan C = $\frac{Height}{Base}$ 

Tan C = $\frac{AB}{AC}$

Hence Tan C = $\frac{3}{4}$ 

4 0

3 years ago

The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i

hram777 [196]

In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78

6 0

3 years ago