Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - $^9C_1=9$

Number of ways for second place - $^8C_1=8$

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - $^8C_1=8$

Number of ways for second place - $^7C_1=7$

Total number of different tickets are possible is

$n=9\times 8\times 8\times 7$

$n=4032$

Therefore, 4032 different tickets are possible.

8 0

3 years ago

If the square root of the length of the hypotenuse of a right triangle is 2 units, what is the sum of the squares of the length

Soloha48 [4]

Hyp^2 = a^2 + b^2

sqrt (hyp) = 2
hyp = 4
hyp^2 = 16 then from above a^2 + b^2 = 16

5 0

3 years ago

0.46 repeating as a fraction

tekilochka [14]

0.46<span> = 7/15 </span>
0.46<span> = 46/99</span>

8 0

3 years ago

Read 2 more answers

What statement about 6x^2+7x-10 is true

nasty-shy [4]

One of the factors is (x+2)

5 0

3 years ago