Determine the Median, Mode, and mean. Please don't answer if you don't know
2 answers:
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Answer:
Part a) The approximate years were 1998 and 2008
Part b) The graph in the attached figure
Step-by-step explanation:
Part a) we have
For
Solve the quadratic equation
we know that
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
substitute in the formula
therefore
The approximate years are
1997+11=2008
1997+1=1998
Part b)
Using a graphing tool
we have
The solution of the system of equations is the intersection point both graphs
The intersection point are (0.99,80) and (11.23,80)
see the attached figure
therefore
The solution part a) is correct
I hope this helps you
if 4 students 12$
10 students? $
?×4=12×10
?=120÷4
?=30$
if 4 students 12$
10 students? $
?×4=12×10
?=120÷4
?=30$