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3 years ago

A heart is randomly chosen 7 out of 12 times from the cards shown

Mathematics

1 answer:

rodikova [14]3 years ago

7 0

Answer:

Experimental probability: 7/12

Theoretical probability: 1/4 or 3/12

Step-by-step explanation:

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9. What is the tan(90-x)?

Aleonysh [2.5K]

$\\ \sf\longmapsto tanx=\dfrac{Perpendicular}{Base}$

$\\ \sf\longmapsto tanx=\dfrac{4}{3}$

$\\ \sf\longmapsto x=tan^{-1}(4/3)$

$\\ \sf\longmapsto x=53°$

$\\ \sf\longmapsto tan(90-x)$

$\\ \sf\longmapsto cotx$

$\\ \sf\longmapsto cot53$

$\\ \sf\longmapsto \dfrac{3}{4}$

$\\ \sf\longmapsto 0.75$

6 0

2 years ago

Read 2 more answers

The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi

pshichka [43]

Answer:

$E(\bar{x}) = 28520$

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

$E(\bar{x}) = \mu = 28520$

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689$

7 0

3 years ago

Can someone help me out pls

Fiesta28 [93]

the answer is d 350000..

6 0

3 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

3 years ago

Find the Simple Interest<br> $700 deposited at an interest rate of 1.5% for 3 years

slega [8]

Answer:

$31.50

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 1.5%/100 = 0.015 per year,

then, solving our equation

I = 700 × 0.015 × 3 = 31.5

I = $ 31.50

The simple interest accumulated

on a principal of $ 700.00

at a rate of 1.5% per year

for 3 years is $ 31.50.

3 0

3 years ago