Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.
Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.
Therefore, the number of possible sets at the dance is 31.
Answer:
∠1 = 96°
∠2 = 84°
∠3 = 84°
Step-by-step explanation:
∠1 = 96°
∠2 = ∠3
∠1 + 96 + ∠2 + ∠3 = 360°
∠2 = (360 - 96 - 96)/2 = 84°
∠3 = 84°
Answer:
If your weekly allowance is 5, then for Christmas week your allowance was 15, then your allowance went up by: 5 =3 - 1 = 2 x 100 =200%.
its none of them? 6y - 10/5 +7y = 12 10 divided by 5 equals 2
it will now look like this: 6y - 2 + 7y = 12
then your going to want to add 2 to both sides of the equation.
it will now look like this: 6y -2 + 7y + 2 = 12 + 2 = 14
simplify: 6y + 7y = 14
add the like terms: 13y = 14
3x + 7y = 14
Subtract 3x from both sides
7y = -3x + 14
Slope is equal to -3.
