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lord [1]
3 years ago
16

What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2Plus or minus 2 StartRoot 5 EndRoot x = ±6Plus or minus 6

StartRoot 3 EndRoot x = ±5Plus or minus 5 StartRoot 2 EndRoot no real solution
Mathematics
2 answers:
ziro4ka [17]3 years ago
6 0

Answer:

c

Step-by-step explanation:

i just got it right on edge.

Serga [27]3 years ago
3 0

Question:

What are the solution(s) to the quadratic equation 50 – x2 = 0?

A) x = ±2Plus or minus 2 StartRoot 5 EndRoot

B) x = ±6Plus or minus 6 StartRoot 3 EndRoot

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

D) no real solution

Answer:

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

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Please explain step by step
Alja [10]

Let's find the value of x

Since the sum of internal angles of a triangle is 180°

therefore,

\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree

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3 years ago
What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?
Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Let (x_1,y_1) be the point (3.5, 2.2) and (x_2, y_2) be the point (1.5, -4.8)

substituting the points in the formula

M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)

=\left(\frac{5}{2}, \frac{-2.6}{2}\right)

=\left(2.5,-1.3\right)

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

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3 years ago
The ratio 20:40:100 in its simplest form.
Gala2k [10]

Answer:

1 : 2 : 5

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20 : 40 : 100 ( divide each part of the ratio by 20 , the HCF of 20, 40, 100 )

= 1 : 2 : 5

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