Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
B is the correct answer
hope this helps
Answer:
5
Step-by-step explanation:
1/3 is only 0.33 and 0.33 isnt higher than 0.50, so you cant round anything. 5 is the answer.
Answer:
5 2/5
Step-by-step explanation:
Multiply by (3 3/5)x/(1 1/2):
x = (2 1/4)(3 3/5)/(1 1/2) = (9/4)(18/5)(2/3) =27/5
x = 5 2/5
The scenario described above is like dividing a right cone from the vertex down to the center for the base. The polygon that can be formed from the division or in this case slicing is a triangle. Thus, the answer to this item is letter B.