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nadezda [96]
3 years ago
6

PLEASE HELP!!! GIVING BRAINLIEST

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:Column one answers:

1: 490

2:396

3.18

4.10

Column 2:

1. 490

2.396

3.18

4.100

Column 3:

1.490

2.396

3.18

4.100

Hope this helps if you need more then just ask

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Work out the balance for £240 invested for 20 years at 7% per annum
Luda [366]

Step-by-step explanation:

It depends in the type on interest

Simple Interest

PxRxT

£240 x 0.07x 3 = £50.4

£240 + £50.4 = £290.4

Compound Interest

Px(1+R)^T

£290.4 x (1 + 0.07)³ = £355.7524872= €355.76

5 0
3 years ago
How to simplify 4x^-3<br><br><br><br> Is the answer 1/4a^3 ?
Rudik [331]
The exponent only applies to the x not the 4
so only the x has permission to move to the denominator
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4 0
4 years ago
Can you please help !? its due at 1:00 pm. (i will mark you brainlest) can you show work if you can?
11111nata11111 [884]

Answer:

10) 9*9*9*9 = 6561

11) 2*2*2 = 8

12) 3*3*3*3*3 = 243

13) 4*4*4 = 64

14) 6*6*6*6*6 = 7776

15) 5*5*5*5 = 625

16) 8.5*8.5*8.5 = 614.125

17) 1.3*1.3 = 1.69

18) 7*7*7*7 = 2401

Used a calculator

8 0
3 years ago
The number of fives is 3 more than six times the number of tens. Let t represent the number of tens. Write an expression for the
bixtya [17]

Answer:

The required expression is f = 3+6t

Step-by-step explanation:

Let t represent number of tens

Let f represent number of fives

So, the expression for number of fives can be formed by using:

The number of fives is 3 more than six times the number of tens.

f = 3+6t

So, the required expression is f = 3+6t

4 0
3 years ago
The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
3 years ago
Read 2 more answers
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