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earnstyle [38]
3 years ago
11

64 add 2km add 1/2km add 1/4km in m

Mathematics
1 answer:
klasskru [66]3 years ago
4 0
I dont no why no abcd 
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oee [108]

Step-by-step explanation:

The answer of the question number 1 is b

The answer of the question number 2 is also c

The answer of the question number 3 is b

The answer of the question number 4 is a

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gladu [14]

THE ANSWER IS<em> -8 </em>

<em />

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3 years ago
1.In a right triangle, &lt;A and &lt;B are acute. Find the value of csc A, when tan A = 8/15.
bekas [8.4K]

Answer:

(1)csc A=\dfrac{17}{8}

(2)sec A=\dfrac{17}{15}

Step-by-step explanation:

<u />Tan A=\dfrac{8}{15}\\$In Trigonometry, $Tan A=\dfrac{Opposite}{Adjacent}\\$Therefore:\\Opposite=8, Adjacent=15<u />

Using Pythagoras theorem

Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=8^2+15^2\\Hypotenuse^2=289\\Hypotenuse^2=17^2\\Hypotenuse=17

<u>Question 1</u>

Now, cosecant = 1/sin

Therefore:

csc A=\dfrac{Hypotenuse}{Opposite}\\csc A=\dfrac{17}{8}

<u>Question 2</u>

Now, secant = 1/cos

Therefore:

sec A=\dfrac{Hypotenuse}{Adjacent}\\sec A=\dfrac{17}{15}

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thank you

Step-by-step explanation:

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