3 years ago

Happy book lovers day

1 answer:

6 0

Answer:

thank you

Step-by-step explanation:

You might be interested in

MissTica

Is this algebra?, i can help you with thats the suject

8 0

3 years ago

Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

6 0

2 years ago

leonid [27]

Answer: Responding for points

Step-by-step explanation:

7 0

3 years ago

katovenus [111]

$10xy^2(3x^3-5x)-2x^2y(6y^3+3y)=\\\\=30x^4y^2-50x^2y^2-12x^3y^4-6x^2y^2=\\\\=\boxed{30x^4y^2-12x^3y^4-56x^2y^2}$

3 0

2 years ago

OLga [1]

Answer: Im not completely sure but my best guess is 21. the tree is 21 feet tall

Step-by-step explanation:

4 0

3 years ago