Answer:
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Options:
A) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
B) Reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
D) Reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Explanation:
The null hypothesis H0: µ=43°F (a true mean temperature maintained by refrigerator is equal to 43°)
The alternative hypothesis Ha: µ<>43 (a true mean temperature maintained by refrigerator is not equal to 43).
A type II error does not reject null hypothesis H0 when it is false. Therefore, the type II error for the test fails to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
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Answer:</h3><h3>

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










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<h3>hope it helps...</h3><h3>have a great day!!</h3>
Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
In a reflection across the y-axis the y-coordinate remains the same, but the x-coordinate is transformed into its opposite
we have
The reflection of f(x) across the y-axis is equal to the function g(x)

The graph in the attached figure
Y=2/3x+2/3
I hope this helps!
Answer:
The equations that represent the reflected function are


Step-by-step explanation:
The correct question in the attached figure
we have the function

we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore

The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)

An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are

