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BabaBlast [244]
3 years ago
14

Solve eight and two fourths minus three and one third

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

5 1/6

Step-by-step explanation:

Rewriting our equation with parts separated

=8+2/4−3−1/3

Solving the whole number parts

8−3=5

Solving the fraction parts

2/4−1/3=?

Find the LCD of 2/4 and 1/3 and rewrite to solve with the equivalent fractions.

LCD = 12

6/12−4/12=2/12

Reducing the fraction part, 2/12,

2/12=1/6

Combining the whole and fraction parts

5+1/6=5 1/6

You might be interested in
15 points! The data set shows the weights of pumpkins, in pounds, that are chosen for a photograph in a farming magazine. The re
vladimir2022 [97]

Answer:

Step-by-step explanation:

a). Mean of the given data set = \frac{32+28+18+40+22}{5}

                                                  = 28

b).   x                     x-\overline{x}               (x-\overline{x})^2

     32          32-28 = 4                    16

     28          28 - 28 = 0                  0

     18           18 - 28 = -10                100

     40          40 - 28 = 12                 144

     22          22 - 28 = -6                 36

                                                 \sum({x-\overline x})^2 =  296          

c). Standard deviation = \sqrt{\frac{\sum (x-\overline{x})^2}{n}}

                                     = \sqrt{\frac{296}{5} }

                                     = 7.69

d). Mean of the new set of weights = \frac{32+33+34+35+36}{5}

                                                          = 34

   Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).

7 0
3 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
Determine the slope of the line given the points (2,1) and (4,0)
kipiarov [429]

The slope is the change in Y over the change in X.


Slope = (0 - 1) / 4-2)

= -1/2

The slope is -1/2

6 0
3 years ago
The volume of this CONE is 175π cubic units.
yulyashka [42]

Answer:

1649.33 units³

Step-by-step explanation:

Let the height and the radius be known as "h" and "r" respectively.

<u>Formulae(s):</u>

  • Volume of cylinder: πr²h
  • Volume of cone: πr²h/3

Clearly, we can see that the volume of the cylinder is three times greater than the volume of the cone as,

  • ⇒ πr²h = 3(πr²h/3)
  • ⇒ πr²h = πr²h (True)

<u>Determining the volume of the cylinder;</u>

  • ⇒ Volume of cylinder = Volume of cone × 3
  • ⇒ Volume of cylinder = 175π × 3
  • ⇒ Volume of cylinder = 525π
  • ⇒ Volume of cylinder = 1649.33 units³   (2 d.p)

Therefore, the volume of the cylinder is 1649.33 units³.

6 0
2 years ago
Determine the intercepts of the line. 7x-5=4y-6
den301095 [7]
<span>1/4= y-intercept
</span><span>-1/7=  x intercept </span>
7 0
4 years ago
Read 2 more answers
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