Help pls l need some help
1 answer:
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Answer:
The system that models the situation is:
The solution is:
(9, 6)
Step-by-step explanation:
We must write the equations as indicated in the problem.
The sum of twice a number and another number is 24
<em>a number:</em> x
<em>other number:</em> y
Then
The difference of twice the first number and the other number is 12
<em>first number: </em> x
<em>other number:</em> y
Then:
The system that models the situation is:
To solve the system we add both equations to find the value of x
---------------------
The solution is:
(9, 6)
The absolute value function |<em>x</em>| always returns a non-negative number. It takes any number <em>x</em> and returns <em>x</em> if it's already non-negative, or -<em>x</em> if it is negative in order to make it positive.
For the equation
-3 + 4 |2<em>x</em> - 5| = 14
rearrange terms to get
|2<em>x</em> - 5| = 17/4
Now,
• if 2<em>x</em> - 5 ≥ 0, then |2<em>x</em> - 5| = 2<em>x</em> - 5. Then
2<em>x</em> - 5 = 17/4
• and if instead 2<em>x</em> - 5 < 0, then |2<em>x</em> - 5| = -(2<em>x</em> - 5), so that
-(2<em>x</em> - 5) = 17/4, or
2<em>x</em> - 5 = -17/4
In the first case,
2<em>x</em> - 5 = 17/4
2<em>x</em> = 17/4 + 5 = 37/4
<em>x</em> = 37/8
In the second case,
2<em>x</em> - 5 = -17/4
2<em>x</em> = -17/4 + 5 = 3/4
<em>x</em> = 3/8