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2 years ago

PLZ HELP x + y - 6 =0 x - y = 0 what is the solution of the system? (-3,3) (3,-3) (3,3)

Mathematics

1 answer:

Molodets [167]2 years ago

5 0

Answer:

(3, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Step-by-step explanation:

Step 1: Define Systems

x + y - 6 = 0

x - y = 0

Step 2: Rewrite Systems

x + y - 6 = 0

Add 6 on both sides: x + y = 6

Step 3: Redefine Systems

x + y = 6

x - y = 0

Step 4: Solve for x

Elimination

Combine 2 equations: 2x = 6
Divide 2 on both sides: x = 3

Step 5: Solve for y

Define equation: x - y = 0
Substitute in x: 3 - y = 0
Subtract 3 on both sides: -y = -3
Divide -1 on both sides: y = 3

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Determine whether the following statement regarding the hypothesistest for two population proportions is true or false.

murzikaleks [220]

Answer:

False

Step-by-step explanation:

Let p1 be the population proportion for the first population

and p2 be the population proportion for the second population

Then

$H_{0}$ p1 = p2

$H_{a}$ p1 ≠ p2

Test statistic can be found usin the equation:

$z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample population proportion for the first population

p2 is the sample population proportion for the second population

p is the pool proportion of p1 and p2

n1 is the sample size of the first population

n2 is the sample size of the second population.

As |p1-p2| gets smaller, the value of the test statistic gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.

As the p-value gets higher, the null hypothesis is less likely be rejected.

7 0

3 years ago

Someone please help me :( I have no idea what I’m doing here

siniylev [52]

SORRY I REALLY DONT KNOW

3 0

3 years ago

the vertex of this parabola is at (2,-1). when the y-value is 0, the x-value is 5. what is the coefficient of the squared term i

timama [110]

We know that

case a)
the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.

Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1

Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1

the answer is
a=1/9

case b)
the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h,
where (h, k) is the vertex.

Using our vertex, we have:
x=a(y+1)²+2,
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2

the answer is
a=3

see the attached figure

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3.25g+2=t is your function

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