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The rate of change in z at (4,9) as we change x but hold y fixed is =
3/[2sqrt(3x+2y)] put x = 4 , y = 9 = 3/[2sqrt(12+18) = 3/[2sqrt(30)] The
rate of change in z at (4,9) as we change y but hold x fixed is =
1/sqrt(3x+2y) put x = 4, y =9 = 1/sqrt(30)
Answer:
-7
Step-by-step explanation:
HOPE THIS HELPS
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>