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the ratio of weight of an object on planet A to the weight of the same object on planet B is 100 to 3. if an elephant weights 22

ipn [44]

Make a proportion.

$\frac{planet A}{planet B}$ ⇒ $\frac{100}{3}$ = $\frac{2200}{x}$
Solve for x to find the weight of the elephant on planet B. Cross multiply; (100)(x) and (3)(2200).

You now have:
100x = 6600.
Divide both sides by 100.

x = 66

The elephant would weigh 66 pounds on planet B.

5 0

3 years ago

Solve this and I’ll give u 5 stars and brainleist

Darina [25.2K]

Answer:

notice: temperature rises quickly at sunrise, and drops before sunset
wonder: whether this location is shaded by mountains later in the day

Step-by-step explanation:

<u>notice</u>

The temperature starts off below zero in the early morning and stays cold until the sun comes up. Then it warms rapidly to an above zero temperature that peaks in early afternoon. Once the sun gets lower, the temperature starts cooling off again. (The daily temperature range of 25-27 degrees is pretty typical for partly-cloudy sky conditions and stable weather.)

<u>wonder</u>

We wonder if this isn't a location that is on the east- or north-side of a mountain, or in a mountain valley, where the sun hits it early and is shaded later in the day. (The topo map attached seems to show it is in such a location.)

8 0

3 years ago

The number of ferryboat trips r(c) needed to transport c cars in 1 day can be found using the function f(c)=c/20. If there are n

xz_007 [3.2K]

<h2>Hello!</h2>

The answer is:

The range of the given function, f(c) is

$f(c)\leq 250$

To solve the problem we need to remember that a function is a relationship between an input usually called "x" (domain) and an output, usually called "y" and it's also the range of the function.

$f(x)=y$

We are given a relationship (a function) between the ferryboat trips "c" and the number of cars transported per day.

$f(c)=\frac{c}{20}$

Also, we know that there are not more than 5000 cars transported by the ferryboat, so, let's make this value our input, in order to find the output (range) of the given function.

So, if

$c=5000$

Evaluating, we have:

$f(5000)=\frac{5000}{20}=250$

Hence, the range of the function knowing that there are not more than 5000 cars transported by the ferryboat (daily) the range is all the numbers that are less or equal to 250.

$f(c)\leq 250$

Have a nice day!

8 0

3 years ago

A cell phone provider offers a plan that costs $30 per month plus $0.10 per text message sent or received. A compatible plan cos

WITCHER [35]

Answer: There would have to be 200 text messages fro both plans to cost the same each month.

Step-by-step explanation:

8 0

3 years ago

NEED HELP ASAP PLZ!!!!!

nikdorinn [45]

3/25

4/38=2/19

54/7=7 5/7

48/9=16/3=5 1/3

5 0

4 years ago