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frez [133]
2 years ago
10

Let ​f(x)=x2+3x−10​. Enter the x-intercepts of the quadratic function in the boxes. x = and x =

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
3 0

Answer:

X= 2.

X= -5.

Step-by-step explanation:

Hope it was helpful ;)

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Please explain your answer. THX!
Elden [556K]

Answer:

see explanation

Step-by-step explanation:

(3)

Given cosΘ = - \frac{4}{5}

Then by Pythagoras' theorem the third side is 3 ( 3,4, 5 triangle )

Since Θ in second quadrant then sinΘ > 0

sinΘ = \frac{3}{5}

Using the trigonometric identity

sin2Θ = 2sinΘcosΘ, then

sin2Θ = 2 × \frac{3}{5} × - \frac{4}{5} = - \frac{24}{25}

(4)

Using the trigonometric identity

cos(x - y) = cosxcosy + sinxsiny

note cos15° = cos(45 - 30)°

cos(45 - 30) = cos45cos30 + sin45sin30

                    = ( \frac{\sqrt{2} }{2} × \frac{\sqrt{3} }{2}) + (\frac{\sqrt{2} }{2} × \frac{1}{2})

                    = \frac{\sqrt{2(\sqrt{3}+1) } }{4}

         

4 0
3 years ago
a father is 24years older than his son. if the son is x years old, how old is the father and if the ratio of their ages is 5:2,
yan [13]

x+25/x=5/2

5x=2(x+24) 5x=2x+48

5x-2x=48

3x=48 3x/3=48/3

the age of son=16

father=24+x 24+16=40

F=40 s=16

40/16=5:2

6 0
3 years ago
Find the arc length, x, when<br> r= 8 and 0 = 5 radians.
lys-0071 [83]

Answer:

Arc Length = 40

Step-by-step explanation:

Arc Length Formula:  S = rΘ

R = radius

Θ = Radians

<u>Step 1:  Identify the radius and the radian angle</u>

R = 8

Θ = 5 radians

<u>Step 2:  Plug into the equation</u>

S = (8)(5)

<u>Step 3:  Solve</u>

S = 40

Answer:  Arc Length = 40

7 0
3 years ago
Select all expressions that are equivalent to 5x + (x+6) + 3x.
liraira [26]
The correct answer is 9x+6.
5 0
3 years ago
Read 2 more answers
I am a square. One of my side is 9 feet long. What is my area?
Stella [2.4K]

Hello from MrBillDoesMath!

Answer:

81 ft^2

Discussion:

The area of a square is (length of a side)^2.  In this case,

Area = 9^2 = 81


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


8 0
3 years ago
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